4x - $\frac{3x + y}{8}$ - $\frac{x – 3y}{4}$
Work out the brackets first
= $\frac{3x + y – 2 (x – 3y)}{8}$
= $\frac{3x + y – 2y + 6y}{8}$
= $\frac{x + 7y}{8}$
Therefor 4x – [$\frac{x + 7y}{8}$]
Remove the brackets
4x - $\frac{x}{8}$ - $\frac{7y}{8}$
= $\frac{32x – x – 7y}{8}$ = $\frac{31x – 7y}{8}$
johnmulu answered the question on March 6, 2017 at 05:38
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